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7x^2-72x+128=0
a = 7; b = -72; c = +128;
Δ = b2-4ac
Δ = -722-4·7·128
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-40}{2*7}=\frac{32}{14} =2+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+40}{2*7}=\frac{112}{14} =8 $
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